# Power loss in a circuit help

by poopoo16
Tags: circuits
 P: 5 ok consider the circuit. what is the power loss in the 20 ohm resistor in J/s? ok so what i did was that.... and i dont know where to go after... please help Attached Thumbnails
HW Helper
P: 3,031
 Quote by poopoo16 ok consider the circuit. what is the power loss in the 20 ohm resistor in J/s? ok so what i did was that.... and i dont know where to go after... please help
That's a good start. Now what about the 6 ohm resistor?
 P: 2,218 Reduce the circuit to an equivalent resistor, find the flowing current, and from there use your power equations to find the power. You are on the right track.
P: 5
Power loss in a circuit help

 Quote by OlderDan That's a good start. Now what about the 6 ohm resistor?

that s my question... dont know how to treat the 6 ohms... do i add it to the 4?

and then use P=IV where I=V/R?...if i do that, its give me 1...and that is not the right answer...
Emeritus
PF Gold
P: 2,977
 Quote by poopoo16 that s my question... dont know how to treat the 6 ohms... do i add it to the 4?
Yes, because it's in series with the other two. Be careful, however, in the power calculation. Is the current flowing through the 20 ohm resistor the same as through the whole circuit?
 P: 5 well, after u combine the 2 parallel ones, its no longer going thru the 20 per se right, its going thru a 6 and a 4?...soo... it then a series right?
 P: 5 so... R=10 V=10 I=V/R hence I=10/10? meanning P=IV P=(1)10...?