Solenoid 30cm long and 8cm in diameter

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SUMMARY

The discussion focuses on calculating the magnetic field strength at the center of a solenoid measuring 30cm in length and 8cm in diameter, powered by a 12-volt car battery using #18 gauge copper wire. The magnetic field strength (B) is derived using the formula B=(μ₀*N*I)/L, where μ₀ is the permeability of free space, N is the number of turns, I is the current, and L is the length of the solenoid. The user initially struggles to calculate the current (I) from the voltage and resistance but later arrives at a magnetic field strength of approximately 3740T using a modified formula. The resistance of the copper wire and its dimensions are crucial for accurate calculations.

PREREQUISITES
  • Understanding of solenoid physics and magnetic fields
  • Familiarity with Ohm's Law and electrical resistance
  • Knowledge of wire gauge specifications, specifically #18 gauge
  • Basic proficiency in using formulas involving permeability and magnetic field calculations
NEXT STEPS
  • Research the formula for calculating the number of turns (N) in a solenoid
  • Learn about the effects of wire gauge on resistance and current flow
  • Explore the concept of magnetic field strength in different solenoid configurations
  • Investigate practical applications of solenoids in electrical engineering
USEFUL FOR

Electrical engineers, physics students, hobbyists building electromagnetic devices, and anyone interested in the practical applications of solenoids in circuits.

Lindz779
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You have a 12 volt car battery and a supply of #18 gauge copper wire. If you make a solenoid 30cm long and 8cm in diameter, winding two layers of wire along the length of the solenoid, what will be the strength of the magnetic field at the center of the solenoid when connected to the car battery? #18 gauge wire has a diameter of 1.02mm.

B=(mu_0*N*I)/L i have B=((4pi*10^7Tm/A)*(294.11turns)*(I))/(.3m) the resistance of copper is 1.7*10^-8 but I am not sure how to get from the 12 volts to the current (I) i have worked this problem a few different ways and i haven't come up with anything that works please help me out
 
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You can find the current just by relating the voltage to the resistance, usually the resistance of a material is given per unit length.. is that the case?
 
answer

i believe i can do that i found a new formula I=(density*Length)/area * volts and when i worked the problem it came out to be something about 3740T.
 

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