Integrating in Spherical Co-Ordinates.

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Homework Help Overview

The discussion revolves around the integration of a function in spherical coordinates, specifically focusing on the conversion of a triple integral from Cartesian to spherical coordinates. The original integral involves variables x, y, and z, and the participants are exploring the correct setup and limits for the spherical coordinate transformation.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the conversion of the integral to spherical coordinates and the challenges associated with setting the correct limits. There are mentions of potential methods such as integration by parts and substitution, as well as concerns about formatting in LaTeX.

Discussion Status

The discussion is active, with participants providing insights on the integrand and limits in spherical coordinates. Some guidance has been offered regarding the integrand's form, and there is acknowledgment of the original poster's progress in correcting their limits.

Contextual Notes

There are indications of difficulties with LaTeX formatting, which may affect the clarity of the problem presentation. The original poster has expressed confidence in their limits after making corrections.

Chaz706
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I have the following Integral

[tex]\int ^1 _0[/tex] [tex]\int _0 ^\sqrt{1-x^2}[/tex] [tex]\int _0 ^\sqrt{1-x^2-y^2}[/tex] [tex]\frac{1}{1+(x^2)+(y^2)+(z^2)} dzdydx[/tex]

(With the limits working properly!)

Converted to spherical Cor-ordinates, I have

[tex]\int ^\frac{\pi}{2} _0[/tex] [tex]\int _0 ^\frac{\pi}{2}[/tex] [tex]\int _0 ^1[/tex] [tex]\frac{1}{1+\rho} \rho^2 sin(\phi) d\rho dr d\phi[/tex]

I've converted the function, but how would I start integrating?
 
Last edited:
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Alright.Transform it in spherical coordinates.But u need the limits...

Daniel.
 
I have the limits... it's just that I can't get them right on Latex (stupid coding! I'm getting it right, it's just not displaying it that way!)

Hang on...

EDIT: Problem above now has working limits, and my original question as intended.
 
Last edited:
A substitution MIGHT work, but i would probably go for integration by parts. Remember sin(phi) is constant for the first integral.
 
[tex]\frac{r^{2}}{1+r}=r-1+\frac{1}{1+r}[/tex]

is all u need.

Daniel.
 
Your integrand in spherical coordinates should be: [tex]\frac{\rho^{2}\sin\phi}{1+\rho^{2}}[/tex]
 
I've got this thanks. Thanks to a form of integration in the back of my book.
 

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