Solution to Optics Lens Problem: Image Distance in f

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Homework Help Overview

The discussion revolves around an optics problem involving a convergent lens, where the original poster seeks to determine the image distance based on the object's distance and the lens's focal length.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the lens formula, with the original poster attempting to use it but encountering difficulties. Questions arise regarding the calculations and the resulting fractions.

Discussion Status

The conversation is active, with participants providing feedback on the calculations and encouraging a re-evaluation of the approach. There is acknowledgment of a mistake made by the original poster, indicating a productive direction in the discussion.

Contextual Notes

There is a focus on the specific values of object distance and focal length, with some participants questioning the calculations leading to unexpected results. The original poster's confusion about the outcome suggests a need for careful review of the mathematical steps involved.

Gshan12
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i need help!

Given: A real object is located to the left of a convergent lens. The object's distance from the lens is 7/3f and its focal length is f. What is the image distance in terms of f?

I tried the formula 1/f = 1/di + 1/do... it didn't work
 
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Gshan12 said:
I tried the formula 1/f = 1/di + 1/do... it didn't work
What makes you think that doesn't work?
 
i got a weird fraction that di= (1-3f^2)/(f^2) and it's not one of the answer choices.
 
I don't see how you get [itex]f^2[/itex]. Redo it, carefully: [itex]o = 7f/3[/itex], so [itex]1/o = 3/(7f)[/itex]. [itex]1/i = 1/f - 3/(7f)[/itex], etc.
 
oh! i made a stupid math mistake...

THANK YOU SO MUCH!
 

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