Proving Velocity Vector Orthogonal to Position Vector on Sphere Surface

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SUMMARY

The discussion centers on proving that a point traveling along the surface of a sphere has a velocity vector orthogonal to its position vector. The equation of the sphere is given as x² + y² + z² = R², where R is the radius. To demonstrate this relationship, participants suggest differentiating the sphere's equation with respect to time using the chain rule and analyzing the resulting dot product between the velocity vector and the position vector. Additionally, the application of curl to the position vector field is proposed as a potential method for proof.

PREREQUISITES
  • Understanding of vector calculus concepts, including differentiation and dot products.
  • Familiarity with the equation of a sphere in three-dimensional space.
  • Knowledge of centripetal motion and its characteristics.
  • Basic understanding of vector fields and the curl operator.
NEXT STEPS
  • Study the chain rule in the context of vector calculus.
  • Learn how to compute dot products between vectors in three-dimensional space.
  • Explore the concept of curl and its applications in vector fields.
  • Review examples of motion on curved surfaces, specifically in relation to spheres.
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Students and professionals in mathematics, physics, and engineering, particularly those interested in vector calculus and motion on curved surfaces.

jessawells
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can someone help me with this problem:

"show that a point is traveling along the surface of a sphere if and only if its velocity vector is orthogonal to its position vector."

I know that it is true intuitively - since in centripetal motion, the velocity is always directed toward the center. but how do you prove this using vector calculus?
 
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jessawells said:
can someone help me with this problem:

"show that a point is traveling along the surface of a sphere if and only if its velocity vector is orthogonal to its position vector."

I know that it is true intuitively - since in centripetal motion, the velocity is always directed toward the center. but how do you prove this using vector calculus?

Then your "intuition" is way off. A point moving along the surface of a sphere is not in "centripetal motion" and the velocity vector is not directed toward the center!

You can assume that your sphere is centered at the origin and, so, has equation x2+ y2+ z2= R2. Differentiate that with respect to time (using the chain rule) and break the result into a dot product of velocity vector with position vector.
 
Couldn't the OP just apply curl to the position vector (field) of the sphere? It's seems more in the spirit of vector calculus.
 

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