How Do I Solve for Planetary Differentials?

  • Thread starter Thread starter one_raven
  • Start date Start date
  • Tags Tags
    Algebra
Click For Summary
SUMMARY

This discussion focuses on solving for planetary gear differentials using a specific equation: (Sr-Sc)/(Ss-Sc)=Ns/Nr. The user is attempting to determine unknown variables in six configurations of a planetary gear system, where S represents speed in RPM and N represents the number of teeth on the gears. The conversation highlights the need for additional relationships to solve for multiple unknowns effectively, emphasizing the importance of ensuring that variables such as (Ss-Sc) and Nr are not zero. The user seeks clarity on the correctness of their derived equations compared to a generic equation for planetaries.

PREREQUISITES
  • Understanding of planetary gear systems and configurations
  • Familiarity with algebraic manipulation and equations
  • Knowledge of gear ratios and their implications in mechanical systems
  • Basic proficiency in spreadsheet software for modeling
NEXT STEPS
  • Research advanced algebra techniques for solving systems of equations
  • Explore the principles of gear ratio calculations in planetary systems
  • Learn about spreadsheet modeling for mechanical engineering applications
  • Investigate additional relationships in planetary gear configurations
USEFUL FOR

Mechanical engineers, automotive engineers, and students studying gear systems who are looking to deepen their understanding of planetary gear differentials and their calculations.

one_raven
Messages
200
Reaction score
0
OK.
Here's the situation:

I am trying to build a spreadsheet to solve for planetary gear configurations.

I have done most of the work already, but I am getting stuck when solving for planetary differentials.

If you don't know, a planetary gear differential is basically a gear set-up that has three shafts that can be used as inputs or outputs.

Let:
S = Speed (in RPM)
N = Number of teeth on the gear
r = ring gear
c = planet carrier
s = sun gear

The relationship can be described by the following equation:

(Sr-Sc)/(Ss-Sc)=Ns/Nr

There are six different configurations I am trying to solve for.

Unfortunately, Algebra and I have been apart for far too long.
Think maybe you can help?

Configuration 1
Ns: known
Nr: known
Sr: known
Sc: known
Ss: not known

Configuration 2
Ns: known
Nr: known
Sr: known
Sc: not known
Ss: not known

Configuration 3
Ns: known
Nr: known
Sr: known
Sc: not known
Ss: known

Configuration 4
Ns: known
Nr: known
Sr: not known
Sc: known
Ss: not known

Configuration 5
Ns: known
Nr: known
Sr: not known
Sc: known
Ss: known

Configuration 6
Ns: known
Nr: known
Sr: not known
Sc: not known
Ss: known

Any help would be greatly appreciated.
Especially if you show me how you did it.
 
Engineering news on Phys.org
Usually, you can only solve for as many unknown quantities as you have equations. Since all you've got is
(Sr-Sc)/(Ss-Sc)=Ns/Nr

That means that you'll need to bring in some additional information for the examples that you give where there are multiple unknowns (2,4, and 6). Perhaps there is some additional relationship that you missed?

In general, you'll probably want to assume that (Ss-Sc) and Nr are both not zero.

Then you can easily convert the equation above into:

Ns=Nr(Sr-Sc)/(Ss-Sc) (Multiply both sides by Nr)
Nr=Ns(Ss-Sc)/(Sr-Sc) (Take reciprocal of both sides, and multiply by Ns)

And these are fairily straightforward after taking a cross product:

(Sr-Sc)/(Ss-Sc)=Ns/Nr
=>
Ns(Ss-Sc)=Nr(Sr-Sc)

Sr=Ns(Ss-Sc)/Nr +Sc
Ss=Nr(Sr-Sc)/Nr +Sc
Sc=(SrNr-SsNs)/(Nr-Ns)

Hope this helps
 
Equation check (Sorry, should have attached to this one)

I compared your equation to a generic equation for planetaries, which is:

(P-1)(Sr/Ss) = P(Sc/Ss) - 1

and which, for a ring-gear planetary:

P = (Nr = Ns)/Ns

If the author of these equations was correct, then the following was derived:

(Sr - Sc)/(Sc - Ss) = Ns/Nr

If so, then your directions will be reversed. I'd like to know which is correct.
Kenneth Mann is online now Reply With Quote
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
3K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 1 ·
Replies
1
Views
6K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 16 ·
Replies
16
Views
4K
Replies
2
Views
3K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K