Help needed with two problems (one a trig question, the other a world prob)

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SUMMARY

The discussion addresses two mathematical problems: solving a trigonometric equation and understanding the concept of visual magnitude in astronomy. The trigonometric equation presented is 13cos²θ - 5cosθ = 12sin²θ - 6, which can be transformed into a quadratic equation by substituting sin²θ with 1 - cos²θ. The visual magnitude problem involves calculating the brightness of stars, specifically comparing Vega's magnitude of 0 with another star's magnitude of -2.4, resulting in a brightness factor of approximately 2.4 times. Additionally, the discussion clarifies how a star's brightness relates to its visual magnitude and contrasts this scale with the Richter scale.

PREREQUISITES
  • Understanding of trigonometric identities and equations
  • Familiarity with visual magnitude and its calculation
  • Knowledge of the relationship between brightness and magnitude in astronomy
  • Basic algebra skills for solving quadratic equations
NEXT STEPS
  • Study the derivation of trigonometric identities, particularly for cos(a + b)
  • Learn about the mathematical principles behind visual magnitude and its applications in astronomy
  • Explore the differences between various scales used in scientific measurements, such as the Richter scale and visual magnitude
  • Practice solving quadratic equations involving trigonometric functions
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Students studying trigonometry and astronomy, educators teaching mathematical concepts, and anyone interested in the relationship between brightness and visual magnitude in stars.

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1. Solve for theta in the interval 0<theta<2pi. Give answers in radians either correct to 3 decimal places or as exact values.

13cos^2 - 5cos = 12sin^2 - 6

3) Scientists use visual magnitude to measure the brighness of a star. The smaller the number, the brighter the star. An increase in magnitude of 1 unit represents a decrease of 60% in the brighness of a star.

a) The star Vega has a magnitude of 0. If a second star has a visual magnitude of -2.4, how many times brighter than Vega is this star?

b) If a star is 15% as bright as Vega is , what is its visual magnitude?

c)How is this scale different from the Richter scale?




For this next question all I need is a basic run through of what I have to do.

4) a and B are both angles in the second quadrant. If sin a = 1/3 and sin B = 2/3, find the exact value of cos (a +b).

Thanks
 
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DLxX said:
1. Solve for theta in the interval 0<theta<2pi. Give answers in radians either correct to 3 decimal places or as exact values.

13cos^2 - 5cos = 12sin^2 - 6

The first thing you should really try doing is copying the problem correctly! That is not the problem you were given because it doesn't make sense! I suspect that the problem is 13 cos2θ- 5 cosθ= 12 sin2θ- 6.
Replace sin2&theta with 1- cos2θ and you have a quadratic equation for cosθ solve for cosθ and then then use a calculator.

3) Scientists use visual magnitude to measure the brighness of a star. The smaller the number, the brighter the star. An increase in magnitude of 1 unit represents a decrease of 60% in the brighness of a star.

a) The star Vega has a magnitude of 0. If a second star has a visual magnitude of -2.4, how many times brighter than Vega is this star?
\
A "decrease" of 60% is the same as 40% or 0.4. -2.4 is a decrease in magnitude of 2.4 so an increase in brightness of 0.4 2.4 times: careful: that is not 2.4*0.4 but (0.4)2.4.

b) If a star is 15% as bright as Vega is , what is its visual magnitude?
"15% as bright" is a decrease of 100-15= 85= (85/40)(40)= (2.125)(40) %

c)How is this scale different from the Richter scale?
Well, how is the Richter scale defined?




For this next question all I need is a basic run through of what I have to do.

4) a and B are both angles in the second quadrant. If sin a = 1/3 and sin B = 2/3, find the exact value of cos (a +b).
If sin a= 1/3 what is cos a? If sin B= 2/3 what is cos B? Do you know a formula for cos(a+b) in terms of cos(a), sin(a), cos(b), sin(b)?

Thanks
 

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