Need help with assignment force question

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    Assignment Force
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SUMMARY

The discussion centers on calculating the electrostatic force between two electrons separated by one meter using Coulomb's law. The formula provided is F = (q1 * q2) / (4πε0d²), where ε0 represents the permittivity of free space. The value of κ is given as 8.9876 x 10^9 N m²/C². Participants are encouraged to apply these constants and the formula to derive the correct force value.

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  • Understanding of Coulomb's law and electrostatic force calculations
  • Familiarity with the concept of permittivity of free space (ε0)
  • Basic knowledge of scientific notation and unit conversions
  • Ability to manipulate algebraic equations
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  • Research the derivation of Coulomb's law and its applications in physics
  • Learn about the significance of permittivity in electrostatics
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  • Study the implications of electrostatic forces in real-world applications, such as semiconductor physics
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Students studying physics, particularly those focusing on electromagnetism, as well as educators seeking to clarify concepts related to electrostatic forces.

Aprilshowers
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I am stumped on this question. Can anyone advise?

The electric charge of an electron is -1.6 X 10 to the -19 power C.
What is the force exerted between two electrons separated by one meter?
 
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The electrostatic force between two charged particles is
[tex]F=\frac{q_1.q_2}{4\pi\epsilon_0.d^2}[/tex]
where [tex]\epsilon_0[/tex] is the permitivity of free space and
[tex]\kappa = \frac{1}{4\pi\epsilon_0} = 8.9876.10^9 N m^2 C^{-2}[/tex]
 
My answer is

<< solution removed by berkeman >>
 
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