Understanding Fluid Pressure: How Deep Can a Snorkeler Safely Dive?

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Homework Help Overview

The discussion revolves around the calculation of how deep a snorkeler can safely dive without risking lung damage due to pressure differences. The subject area is fluid pressure and its effects on the human body while diving.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to calculate the maximum depth using pressure equations but questions their result, indicating a significant discrepancy from the expected answer. Participants raise concerns about unit consistency in pressure calculations.

Discussion Status

Some participants have provided guidance regarding the need for unit conversion in pressure calculations, suggesting that this may be a source of error. The discussion is ongoing, with participants clarifying concepts and addressing misunderstandings.

Contextual Notes

There is a focus on ensuring that pressure values are in consistent units, as the original poster used different units for pressure in their calculations. The problem context is framed within the constraints of a homework assignment, which may impose specific requirements on the approach taken.

physics noob
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human lung can withstand an inside/outside difference of about .06 atm. if a diver is using a snorkel to breathe, how far below the water surface can he get before he is risking lung damage? pressure of outside is the water pressure at that depth, while pressure inside is the pressure of the air being breathed.

this is what i have...

.06 = 1.01e5 / (1.01e5 + 1000(9.8)(h)

the above calc comes from equation P= Po +density(g)(h)...1000 is the density of water given to us, and 1.01e5 is atmospheric pressure,,,,, by solving for h i get an answer of 161.45 m...and not suprisingly I am way off, the correct answer is .62m where did i go wrong here
 
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See the units for pressure you used on LHS and RHS
 
im not sure i understand what you are saying
 
On the left hand side you used pressure in atmospheres (0. 06atm). Whereas in the right hand side you used pressure in Pascals (1.01* 10^5 Pascals).
Since the SI unit of pressure is Pascals (and you used value of g as 9.8 m/sec^2, which is expressed in SI units), you should convert the pressure from atmospheres to Pascals before you calculate.
 
you are right on siddarth,.,,,, thanks a lot
 

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