A 1500kg car slows from 45km/h[E] to 30km/h[E]

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SUMMARY

The discussion focuses on calculating the impulse experienced by a 1500 kg car as it decelerates from 45 km/h to 30 km/h. The conversion of speeds to meters per second is established, with 45 km/h equating to 12.5 m/s and 30 km/h to 8.3333 m/s. The impulse is calculated using the formula I = mdv, resulting in an impulse of -6250 kg·m/s, indicating a decrease in momentum due to braking.

PREREQUISITES
  • Understanding of basic physics concepts such as momentum and impulse
  • Familiarity with the formula I = mdv for calculating impulse
  • Knowledge of unit conversions, specifically from km/h to m/s
  • Basic arithmetic skills for performing calculations
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  • Study the principles of momentum conservation in physics
  • Learn about the relationship between force, mass, and acceleration
  • Explore real-world applications of impulse in automotive safety systems
  • Investigate the effects of braking distance and force on vehicle dynamics
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Students studying physics, automotive engineers, and anyone interested in understanding vehicle dynamics and braking mechanics.

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a 1500kg car slows from 45km/h[E] to 30km/h[E]. What is the impulse from the brakes?
 
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This should probably be posted in the homework help section.

Nautica
 
45km/h = 12.5m/s
30km/h = 8.3333m/s

I = mdv
I = (1500) x (8.333 - 12.5)
I = -6250kgm/s
 

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