Capacitors - problem w/ diagram

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Homework Help Overview

The discussion revolves around calculating the equivalent capacitance between two points in a circuit involving multiple capacitors. The original poster presents values for three capacitors and seeks assistance in determining their combined effect.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the configuration of the capacitors, questioning the clarity of the diagram and the implications of a potential short circuit. There are mentions of calculating capacitance for series and parallel connections, as well as how to approach the problem based on the circuit layout.

Discussion Status

The conversation is ongoing, with some participants providing insights into the calculations involved while others express concerns about the diagram's accuracy. There is no explicit consensus on the correct interpretation of the circuit yet, but guidance on the types of connections is being shared.

Contextual Notes

There are indications of ambiguity in the diagram provided by the original poster, particularly regarding the lower portion where a wire appears to short the capacitor leads. This has led to questions about the intended configuration and assumptions made in the problem setup.

njvc3
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Hello, I was hoping to get some help with this problem..

Find the equivalent capitance between points a and b for
the group of capacitors connected as shown in the following
figure if C1=5.00µF, C2=10.00µF, and C3=2.00µF.

I appreciate the assistance. :smile:
~Val

[diagram attached]
 

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Zz.
 
The lower portion of your diagram is ambiguous. It shows a wire shorting the capacitor leads, but I doubt that is what the problem intended. Show us how you think the problem should be done. What is the equivalent capacitance of capacitors in series, or capacitors in parallel?

https://www.physicsforums.com/showthread.php?t=4825
 
First you calculate the capacitance of the series connection of [tex]C_1[/tex] and [tex]C_2[/tex]. Call it [tex]C_{12}[/tex].
The capacitance of the upper portion of the circuit is given by the parallel connection of [tex]C_{12}[/tex], [tex]C_3[/tex] and [tex]C_{12}[/tex].
The two [tex]C_2[/tex] capacitances of the lower part are short-circuited, so the overall circuit capacitance is the value of the upper part.
 
I merged the duplicate thread you created in EE with this one. Please do not double post!
 
Thanks SGT

Thank you SGT for giving me useful help to the problem..



Btw, it's necessary to get a wider array of people that
may be of some assistance -- THUS the need to post
in different rooms... alright
 

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