Is the Hamiltonian Cycle an NP Problem?

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Discussion Overview

The discussion revolves around the classification of the Hamiltonian cycle problem within computational complexity theory, specifically whether it is considered an NP problem. Participants explore the implications of this classification and its relation to the broader NP vs P question.

Discussion Character

  • Debate/contested

Main Points Raised

  • One participant asserts that the Hamiltonian cycle problem is NP-complete, which is a proven fact and not subject to change.
  • Another participant expresses curiosity about the reasoning behind the initial question regarding the Hamiltonian cycle's classification.
  • A participant mentions a desire to develop an algorithm related to the Hamiltonian cycle, linking it to the unresolved NP=P question.
  • There is a suggestion that if someone has an algorithm for the Hamiltonian cycle, it could imply a solution to the NP=P problem, prompting a light-hearted challenge for a paper on the topic.
  • One participant clarifies that they have an algorithm they wish to test, but they do not claim it will solve the NP=P problem.

Areas of Agreement / Disagreement

Participants generally agree that the Hamiltonian cycle is NP-complete, but there is no consensus on the implications of this classification or the potential of the proposed algorithm to address the NP=P question.

Contextual Notes

Some assumptions about the definitions of NP-completeness and the NP=P problem are present, but these are not explicitly stated or resolved in the discussion.

neurocomp2003
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sup, just realized there is not graphtheory/combinatorial subforums.

is the hamiltonian cycle still considered and NP problem?
 
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The problem of finding a Hamiltonian cycle in a graph is NP-complete (and therefore NP). This is a proven fact; it is not something that is under consideration (and so it will not change in the future).
 
I wonder what thought could have raised this question :)

-- AI
 
having an algorithm that i want to code but I'm lazy. and if the question of NP=P was solved then there was no point =] guess that should have been my question but I just wanted to see if there was apaper out their that said H=P.
 
As master_coda has stated, Hamiltonian is "proved" to be NP-complete.
Now, if i understand your last post, then you seem to have an algorithm for Hamiltonian in which case you have solved the NP=P problem! When are we going to see your paper coming out :D

-- AI
 
hahah i have an algorithm that I would like to try and see if it goes anywhere...not going to say it'll solve NP=P, but i want to see if it can go somewhere.
 

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