Rearranging Equation: Where is My Mistake?

[hexa]

I'm trying to rearange an equation but don't manage to get the right results so I guess the rearranging did not work out properly. Where is my mistake?

Z=Y+(X/W)Ve(^(WU) -1)
Y=0


my sollution:
U=ln (Z/((X/W)U))+1 /W

thanks a lot

hexa

 

[VietDao29]

Z=Y+(X/W)Ve(^(WU) -1)

I don't really get this equation. Can you write it in a clearer way? What's V, and is it e ^(WU - 1) or e ^(WU) - 1?
Viet Dao,

 

[EnumaElish]

my sollution:
U=ln (Z/((X/W)U))+1 /W

What happens to V? Why is there a U on the right? Is that supposed to be V? And yeah, what does e(^(WU)-1) mean? Did you mean to write e^(WU-1)?

 

[HallsofIvy]

I'm trying to rearange an equation but don't manage to get the right results so I guess the rearranging did not work out properly. Where is my mistake?

Z=Y+(X/W)Ve(^(WU) -1)
Y=0


my sollution:
U=ln (Z/((X/W)U))+1 /W

thanks a lot

hexa

I am not clear on what e(^(WU)-1) could mean. I'm going to assume that it was e^(WU-1) (e^WU-1). The other possiblility is e^(WU)- 1 (e^WU-1.

If Y= 0, then the equation is really Z= (X/W)V e^WU-1. Divide both sides by (X/W)V and we have (WZ)/(XV)= e^WU-1. Take the natural logarithm of both sides to get ln((WZ)/(XV))= WU-1. Add 1 to both sides: WU= 1+ ln((WZ)/(XV). Finally, divide both sides by W and you have
U= (1+ ln((WZ)/(XV)))/W.

Of the problem was, in fact, Z= (X/W)V (e^WU-1) then start out the same as above- divide by (X/W)V to get (WZ)/(XV)= e^WU-1.
Add 1 to both sides: e^WU= 1+(WZ)/(XV). Take logarithms of both sides: WU= ln(1+ (WZ)/(XV)). Finally, divide both sides by W:
U= ln(1+(WZ)/(XV))/W.