How Does the Law of Multiple Proportions Apply to Sulfur and Fluorine Compounds?

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The discussion centers on the application of the Law of Multiple Proportions to sulfur and fluorine compounds. Specifically, it examines two compounds where 0.447 g of sulfur combines with 1.06 g of fluorine, and 0.438 g of sulfur combines with 1.56 g of fluorine. The ratio of the masses of fluorine that combine with a fixed mass of sulfur demonstrates the law, as the calculated ratio of these two compounds yields a simple whole number. This confirms that the data illustrates the Law of Multiple Proportions effectively.

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Victor Frankenstein
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Sulfur forms two compounds with fluorine. In one of them it is observed that 0.447 g of sulfur is combined with 1.06 g of fluorine while in the other, 0.438 g of sulfur is combined with 1.56 g of fluorine. Show that these data illustrate the law of multiple proportions.

would (0.447/1.06)/(0.438/1.56) work, why or why not?
 
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Victor Frankenstein said:
Sulfur forms two compounds with fluorine. In one of them it is observed that 0.447 g of sulfur is combined with 1.06 g of fluorine while in the other, 0.438 g of sulfur is combined with 1.56 g of fluorine. Show that these data illustrate the law of multiple proportions.

would (0.447/1.06)/(0.438/1.56) work, why or why not?
All you've done there is write out a number. How would you now show that this number illustrates that the Law of MP is at work in these compounds ?

PS : The illlustration follows directly from evaluating and rewriting that number in a more friendly form.
 

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