
#1
Aug2205, 10:57 AM

P: 355

A sphere of radius R carries a charge density kr(where k is a constant!).What will be the energy of the Configuration??




#2
Aug2205, 11:36 AM

Sci Advisor
HW Helper
P: 1,930

1. Find the potential phi(r) inside the sphere.
2. Integrate rho*phi/2 over the volume of the sphere. 3. The algebra is a bit complicated. I get 35pi^2k^2R^7/72, but check me for errors. 



#3
Aug2205, 11:39 AM

P: 355

Gentleman,Why won't will be find the Potential outside the sphere..
I am very much perplexed with this Energy term..This is interaction energy Pls help logically,i can do the maths involved.!! Pls explain the origin of energy and i think we will integrate over whole space...but i don't have clear idea.! 



#4
Aug2205, 12:07 PM

P: 355

Energy of ConfigurationWell i got the solution as 4pi*k^2*R^7/21*epsilon!! I don't know whether you are correct or me! 



#5
Aug2205, 12:52 PM

HW Helper
P: 508

The energy is due to the work done in configuring the sphere. Consider the sphere of radius r, and add a layer of thickness dr. Calculate the work dw is required to put this layer of charge. Integrate the work dw over the radius 0 to R. This will be the energy of the configuration



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