Average Acceleration during a collision

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SUMMARY

The discussion focuses on calculating the average acceleration of a driver during a collision where a car traveling at 85 km/h strikes a tree, and the driver comes to rest after traveling 0.80 m. Using the SUVAT equations, specifically v² - u² = 2as, the initial velocity (u) is converted to meters per second (23.61 m/s). The average acceleration (a) is determined to be -18.57 m/s², which translates to approximately -1.89 g's, indicating a significant deceleration during the impact.

PREREQUISITES
  • Understanding of SUVAT equations in physics
  • Knowledge of unit conversion from km/h to m/s
  • Familiarity with concepts of acceleration and deceleration
  • Basic algebra skills for solving equations
NEXT STEPS
  • Study the derivation and application of SUVAT equations in various scenarios
  • Learn about the effects of collisions on vehicle safety and occupant protection
  • Explore advanced topics in kinematics, including impulse and momentum
  • Investigate real-world applications of acceleration calculations in automotive engineering
USEFUL FOR

This discussion is beneficial for physics students, automotive engineers, and safety analysts interested in understanding the dynamics of vehicle collisions and the resulting forces experienced by occupants.

tak181
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Hello everyone. I am having a little trouble with this problem and I was wondering if you could give me a hand with it.

A car traveling 85 km/h strikes a tree. The front end of the car compresses and the driver comes to rest after traveling 0.80 m. What was the average acceleration of the driver during the collision? Express the answer in terms of "g's," where 1.00 g = 9.80 m/s^2.

V(0)=85 km/h
X(0)=0
V=0
X=.80 m
 
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Use the suvat eqn

v² - u² = 2as
 
Fermat said:
Use the suvat eqn

v² - u² = 2as
Where v= final velocity, u= initial velocity and s= distance traveled.


Another way to do that problem is to use the two equations

v= u+ at

s= (1/2)at2+ ut

Again, u is initial velocity, v is final velocity, s is distance moved. t now is the time of the collision. You have two equations in two unknowns, a and t.
 

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