What is the technique used to solve a separable differential equation?

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SUMMARY

The technique used to solve the separable differential equation dy/dx=[x(y^2-2)]/(2x^2-6x+4) involves separating variables and integrating both sides. The equation can be rewritten as (xdx)/(2(x-2)(x-1)) = dy/(y^2-1). To solve this, apply partial fractions for the left-hand side and utilize a trigonometric substitution for the right-hand side. This method effectively simplifies the integration process.

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schattenjaeger
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If you have the seperable DE...

dy/dx=[x(y^2-2)]/(2x^2-6x+4)

that eventually ends up

(xdx)/(2x^2-6x+4)=dy/(y^2-1), right

'cuz that's some integration I REALLY don't feel like doing by hand, so I don't want to do the wrong thing
 
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That's

[tex]\frac{x}{2(x-2)(x-1)} dx= \frac{1}{y^2 -1}dy[/tex]

Use partial fractions to do the left hand side, and a trig substitution on the right.
 

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