Train Acceleration Problem: Finding Final Car Velocity at 190m Distance

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SUMMARY

The discussion focuses on calculating the final velocity of the last car of a 90 m long train that accelerates uniformly from rest. The front of the train reaches a speed of 19 m/s as it passes a railway worker located 190 m from the starting point. To find the speed of the last car, one must first determine the acceleration using the known speed at 190 m and then calculate the additional speed gained over the remaining 90 m, resulting in a total distance of 280 m.

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hey could someone tell me how to start this problem? i don't know which formula I'm suppose to use..

A 90 m long train begins uniform acceleration from rest. The front of the train has a speed of 19 m/s when it passes a railway worker who is standing 190 m from where the front of the train started. What will be the speed of the last car as it passes the worker?

is the velocity 19 m/s? and the distance is 190 m?
 
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iS IT GIVEN that the train accelerates or deccelerates? if none of these , then velocity should remain same.

BJ
 
confusedaboutphysics said:
hey could someone tell me how to start this problem? i don't know which formula I'm suppose to use..

A 90 m long train begins uniform acceleration from rest. The front of the train has a speed of 19 m/s when it passes a railway worker who is standing 190 m from where the front of the train started. What will be the speed of the last car as it passes the worker?

is the velocity 19 m/s? and the distance is 190 m?
You need to calculate the rate of acceleration using the speed at 190 meters. Then calculate the speed at 190 + 90 = 280 meters by answering the question "how much additional speed will the train gain when it accelerates over 90 meters?"
 

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