What is the height when the object has half its initial velocity?

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The discussion centers on calculating the height of a ball when it reaches half of its initial velocity, given that the maximum height is 37 meters. The initial velocity is determined to be 26.9 m/s, leading to half of this value being 13.45 m/s. The kinematics equation v = v_0 + at is referenced for solving the problem, with the focus on finding the elevation corresponding to half of the initial velocity.

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I am instructed in a question to find half of the initial velocity if the max. height of a ball going upward is 37 m. I believe I have found the initial velocity to be 26.9 m/s - so I'm thinking the rest should be simple, right?

For instance if I took the kinematics equation v = v_0 + at, I should be able to rearrange and solve for half of v_0, correct? Or something...?

Thanks!

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Morgan
 
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Huh?
If v_o = 26.9 [m/s] , half of v_o = 13.45 [m/s] .

Did you want to find the *time* when v = 1/2 v_o ,
or the elevation where the object has 1/2 v_o ?
Did you want to find the velocity at half the 37 [m] ,
or the elevation at half the rise time?
 
Sorry... I'm looking for the height (elevation) when the object has 1/2 its initial velocity... does that clarify?
 

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