Sharp Turning & Changing Direction: Physics Explained

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Discussion Overview

The discussion revolves around the physics of sharp turning, specifically focusing on the concepts of curvature, direction change, and the application of Newton's Laws of Motion in these contexts. It includes mathematical formulations related to curvature and its implications in motion dynamics.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant states that sharp turning involves the same physics as gentle turning, referencing Newton's Laws of Motion.
  • Another participant provides a detailed mathematical explanation of curvature, including the definition of curvature (\kappa) and its relationship to the tangent vector and velocity.
  • The mathematical formulation includes expressions for acceleration in terms of curvature and velocity, suggesting that sharper curves correspond to larger curvature values.
  • A later reply introduces the concept of 'TNB Physics,' explaining the significance of the tangent, normal, and binormal vectors in relation to curvature.

Areas of Agreement / Disagreement

Participants present differing levels of detail in their explanations, with some focusing on general principles while others delve into mathematical specifics. No consensus is reached on a singular approach or understanding of sharp turning.

Contextual Notes

The discussion includes complex mathematical expressions and assumptions about the definitions of curvature and motion that may not be universally agreed upon. The implications of these mathematical relationships on real-world applications remain open for further exploration.

modeman
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What is the physics of sharp turning; sharp curves and changing direction about those curves?
 
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Unless you have a specific unstated issue in mind then the answer is that it's the same physics as for gentle turning, curves and changing direction, i.e. Newton's Laws of Motion.
 
modeman said:
What is the physics of sharp turning; sharp curves and changing direction about those curves?

Curvature:
[tex]\kappa = \left| {\frac{{d\vec T}}{{ds}}} \right| = \frac{{\left| {\vec T\,'\left( t \right)} \right|}}{{\left| {\vec r\,'\left( t \right)} \right|}} = \frac{{\left| {\vec r\,'\left( t \right) \times \vec r\, {''}\left( t \right)} \right|}}{{\left| {\vec r\,'\left( t \right)} \right|^3 }}[/tex]

Sharper curves have larger values of [itex]\kappa[/itex].

Curvature has its physical applications; for example, let [tex]\vec r ( t )[/tex] represent the position of an object at time [itex]t[/itex]. You know that
[tex]\left\{ \begin{gathered}<br /> \vec T = \frac{{\vec r\,'}}<br /> {{\left| {\vec r\,'} \right|}} = \frac{{\vec v}}<br /> {{\left| {\vec v} \right|}} \Rightarrow \vec v = \left| {\vec v} \right|\vec T \hfill \\<br /> \kappa = \frac{{\left| {\vec T\,'} \right|}}<br /> {{\left| {\vec r\,'} \right|}} = \frac{{\left| {\vec T\,'} \right|}}<br /> {{\left| {\vec v} \right|}} \Rightarrow \left| {\vec T\,'} \right| = \kappa \left| {\vec v} \right| \hfill \\<br /> \vec N = \frac{{T\,'}}<br /> {{\left| {T\,'} \right|}} \Rightarrow T\,' = \vec N\left| {T\,'} \right| = \kappa \left| {\vec v} \right|\vec N \hfill \\ <br /> \end{gathered} \right\}[/tex]

And so, making the necessary substitution,
[tex]\begin{gathered}<br /> \vec a = \vec v \, ' = \left| {\vec v} \right| ' \vec T + \left| {\vec v} \right|\vec T' \Rightarrow \hfill \\<br /> \vec a = \left| {\vec v} \right| '\vec T + \kappa \left| {\vec v} \right|^2 \vec N \hfill \\ \end{gathered}[/tex]

Hope this helps :smile:
 
This is studied under 'TNB Physics' which constitutes the T=Unit Tangent vector N= Principle vector and B Vector . The curvature given by 'k' is defined by rate of change of unit normal vector per unit length.

BJ
 

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