Solving Newton's First Law: Spider Attached to Two Threads

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SUMMARY

The discussion focuses on calculating the tension in two threads attached to a spider, which is motionless and has a mass of 30 mg. According to Newton's First Law, the sum of forces acting on the spider must equal zero. The tension in each thread, T1 and T2, is equal due to symmetry, resulting in a calculated tension of 3.0 x 10^-4 N for each thread, contrary to the initial confusion regarding the values. The correct application of vector forces clarifies the solution.

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  • Understanding of Newton's First Law of Motion
  • Basic knowledge of vector forces
  • Familiarity with tension in strings or threads
  • Ability to perform basic algebraic calculations
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brad sue
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Please ,
Explain me this situation
A spider is attached to two threads of equal length that make a 120o angle with each other. The spider is motionless and its mass is m=30mg.
What is the tension in each thread?

According to the Newton first Law, the sum of the force must be 0.

T1+T2+Fspider=0
since the threads are the same length and symetrical, T1=T2.

Fspider=-3.0 *10-4N

so I found T1=1.5 *10-4N

I am surprised to see that the answer is 3.0 *10-4N on each thread

please now I am confused! help
 
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Forces are vectors...
 
Hurkyl said:
Forces are vectors...
ok but how it is help me please?
 

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