How to write this logarithmic equation as a power

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    Logarithmic Power
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Homework Help Overview

The discussion revolves around transforming the logarithmic equation ln(y) = 3 + 0.2x into an exponential form, specifically y = pq^x. The subject area involves logarithmic and exponential functions.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between logarithmic and exponential forms, with attempts to manipulate the equation into the desired format. Questions arise regarding the application of exponential properties and the correct interpretation of the transformations.

Discussion Status

Some participants have offered guidance on using properties of exponents and logarithms, while others express confusion about the transformations and seek clarification. Multiple interpretations of the equation's manipulation are being explored.

Contextual Notes

There appears to be uncertainty regarding the correct application of exponential rules and the final form of the equation, with participants questioning their previous attempts and the validity of their expressions.

brandon26
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how can the relationship between y and x in the form Iny = 3+0.2x, be written in the form y = pq^x.

I tried many ways, but can't find the righ format, someone help please?
 
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1) ln(a)=x means a=exp(x)
2) exp(x+y)=exp(x)*exp(y)
 
yes, but that doesn't help me? :confused:
 
1)lny=3+0.2x => y=exp(3+0.2x). Now you do the 2).
 
Oh right. Thank you. I got y=exp(3) * exp (0.2x).
That becomes y = exp(3+0.6) * exp(x)
 
Sorry that is wrong
 
y = exp(0.2)x + exp(3). is that right?
 
sorry, i forgot this one:)
3)a^(b*c)=(a^b)^c
 
Last edited:

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