Stuck on Physics Assignment: Finding Force Required to Move Block Up Wall

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SUMMARY

The discussion centers on calculating the force required to move a 3.8 kg block up a vertical wall when pressed against it at a 35-degree angle. The coefficient of static friction is 0.54, and the normal force is determined by the x component of the applied force vector. To initiate movement, the applied force must overcome both the gravitational force acting downward and the static frictional force, which is calculated as the product of the normal force and the coefficient of static friction.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of vector components in physics
  • Familiarity with static friction and its coefficient
  • Ability to perform basic force calculations
NEXT STEPS
  • Study the concept of normal force in inclined planes
  • Learn about vector resolution in physics
  • Explore static friction calculations in detail
  • Review problems involving forces acting at angles
USEFUL FOR

This discussion is beneficial for first-year university physics students, particularly those studying mechanics and waves, as well as anyone seeking to understand the application of forces in real-world scenarios.

Kumar9
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Hi all, I'm in my first year of university physics (mechanics and waves) and am stuck on an assignment question. The question itself is not complicated, but I feel as though I'm skipping over something important. The question is:

A 3.8 kg block is pressed against a vertical wall by a force that is applied 35 degrees to the horizontal. The block is initially at rest and the coefficient of static friction is 0.54, so what force must be applied to begin moving the box up the wall?

From my understanding, the normal force would be equal to the x component of the force vector, which would allow the maximum force of static friction to be calculated. I don't quite know how to proceed from there...so any help would be greatly appreciated.
 
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The frictional force is given by the x component of the applied force multiplied by 0.54. The frictional force will resist any other applied force. The applied forces are the y component of the applied force (pointing up), and the y component of the gravitational force (pointing down).

That should get you started. Good luck.

Carl
 
Yes, that's what I needed to be confirmed. Thank you.
 

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