Is it possible to integrate this new function?

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The discussion focuses on the integration of the function d(1-v) / (1 - v^4) = dt. It confirms that integration is possible by first rewriting 1 - v^4 as (1 - v^2)(1 + v^2) and applying partial fraction decomposition. Additionally, the differential d(1-v) is rewritten as -dv, leading to the final result of -1/2 tan^{-1}(v) - 1/4(ln(v) - 1)/(ln(v) + 1).

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Doing a friction fluid denisty question and have to figure out why it can't be done.

d(1-v) / (1-v) = dt would integrate to ln |1-v| = t + c



now I am faced with the same integration but the function has changed and now I am staring a

d(1-v) / (1 - v^4) = dt is it possible to integrate that?
 
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Yes. First, write [itex]1-v^4[/itex] as [itex](1-v^2)((1+v^2)[/itex] then do a partial fraction decomposition. Also, rewrite d(1-v) as -dv and you should end up with something like

[itex]-\frac {1}{2} \tan^{-1}v - \frac {1}{4}\frac{\ln v -1}{\ln v + 1}[/itex]
 

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