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Old Oct6-05, 11:24 AM                  #1
bayan

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Posts: 157
My Report

This is my report on an experiment that I have done and I really needed the latex codes to generate the equations. I have done the other parts of the report on other PC.

Do they seem to be ok? (the errors, like the max possible value and min possible value)

no help is really needed, rather I want to know what you think of it, any where I can improve or anything I should drop (unnecesary things)

Thank you!

for LaTeX Code: \\lambda
LaTeX Code: \\lambda =\\frac{18.5}{6.5}
LaTeX Code: \\lambda = 2.85 cm


This indicates that the apprxmiate wavelength is LaTeX Code: 2.85 cm with a error margin of LaTeX Code: ^+_-0.03

now to find the spacing between the ball bearings we can use the first angle and LaTeX Code: Braggsingle-quotes equation to find the other angles.

LaTeX Code: n1

LaTeX Code: 1\\lambda =2dSin14^o

LaTeX Code: d=\\frac {2.85}{2Sin14^o}

LaTeX Code: d= 5.89 cm


Now we can find values for other angles that correspond to this equation.

LaTeX Code: n2

LaTeX Code: \\theta=Sin^-^1 \\frac {5.7}{11.78}

LaTeX Code:  \\theta = 28.9^o

for LaTeX Code: n3

LaTeX Code: \\theta= Sin^-^1 \\frac {8.55}{11.78}

LaTeX Code: \\theta = 46.5^o

for LaTeX Code: n4

LaTeX Code: \\theta = Sin^-^1 \\frac {11.4}{11.78}

LaTeX Code: \\theta = 75.4^o

there is no LaTeX Code: n5 as the equation makes no scence and there is no value for LaTeX Code: sin grater than LaTeX Code: 1





Now we come to the errors that were involved in this experiment!

The wavelength was within a error range of LaTeX Code: ^+_-0.03 cm .

the angle was read to the nearest degree so it was really LaTeX Code: 14^o  ^+_-1^o which then makes the d value lower and higher.

For example the maximum d is when angle was LaTeX Code: 14^o-1^o=13^o

Now we get the new LaTeX Code: d=\\frac {2.88}{2sin13^o} which is LaTeX Code: 6.4 cm

The minimum value obtainable from these sets of result are as followed.

LaTeX Code: d=\\frac {2.82}{2sin14^o} which is LaTeX Code: 5.82 cm

For LaTeX Code: n2 the angle was LaTeX Code: 28.9^o which could have been altered such that maximum is LaTeX Code: \\theta = sin^-^1 \\frac {5.76}{11.64} which is about LaTeX Code: 29.7^o and the minimum value could have been
LaTeX Code:  \\theta = Sin^-^1 \\frac {5.64}{12.8} in which the angle is about LaTeX Code: 26.1^o

This just repeats untill the last value of reflection angle.

I will show that the last angle would still exist even with the big error probability.

For Max LaTeX Code: \\theta the LaTeX Code: \\theta=2.88 which results LaTeX Code: \\theta = sin^-^1 \\frac {11.52}{11.64} which is LaTeX Code: 81.8^o and for Min the angle is LaTeX Code: \\theta = sin^-^1 \\frac {11.28}{12.8} which happens to be about LaTeX Code: 61.8^o

So infact the errors did not have a huge impact on the resultst that we were really intrested (which is to find how many ball bearings there is!) but if we were to have a diffrent aim those errors would have made it really hard (for example if we wanted to see what exactly the crystall looks like)
 
Old Oct6-05, 02:09 PM                  #2
Moonbear
 
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