Solving f(x) = 5^sqrt(2(x^2)-1)

[ludi_srbin]

f(x)=5^sqrt(2(x^2)-1)

I got that range is (1, to infinity)

Is it correct?

 

[Fermat]

What does f equal if x = -2 ?

 

[ludi_srbin]

5^sqrt(7). If x=sqrt(2)/2, then I get F(x)=1

 

[Skippy]

Isn't x= sqrt(1/2) the lowest you can go?

 

[Fermat]

By range, do you mean the range of x-values or y-values ?

If it's for the y-values then your range of 1 - infinity is correct.

If it's for the x-values, then that's a bit different.

 

[ludi_srbin]

For y values. They teach us to call x-values domain.

 

[Fermat]

That's right.
I use domain for x-values and co-domain for y-values.
But I've seen range used for x-values before.