Capacitance equired to store an energy of

[mr_coffee]

Hello everyone. The question is:
What capacitance is required to store an energy of 8 kWh at a potential difference of 600 V?
\This seems like a simple problem..our professor hasn't went over this yet but i saw in the book. P = U/t; I also saw; U = 1/2CV^2; So they gave me U right? because P = U/t, so U = 8 kWh, i converted this into 8kWsecond, by doing this:
8kwh x 3600sec = 28800kws; I then used:
C = (2U)/v^2; C = [2*28800]/(600)^2 = .16 which was wrong, i also tried just using 8, and 8/3600, all didn't work.

 

[mukundpa]

1 KWH = 1*1000*3600 J = 3.6 x 10^6 J (S.I. Unit of energy)

 

[vanesch]

8kwh x 3600sec = 28800kws;

There is still the KILO in there, which you should convert numerically (hint: 1000:-)

 

[mr_coffee]

Ahhh thank you guys, worked great :)