Dopler effect


by squib
Tags: dopler, effect
squib
squib is offline
#1
Oct9-05, 08:46 PM
P: 40
A sound wave travels at a frequency 2.25 MHz through a pregnant woman's abdomen and is reflected from the fetal heart wall of her unborn baby. The heart wall is moving toward the sound receiver as the heart beats. The reflected sound is then mixed with the transmitted sound, and 87.0 beats per second are detected. The speed of sound in body tissue is 1510 m/s.

I did 87 = x - 2,250,000
F = 2,250,087

so then 2,250,087 = 2,250,000 (1510 + V_heart)/150
which came to .0584 m/s
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lightgrav
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#2
Oct9-05, 09:11 PM
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you divided by 1510 m/s, right?
Did you have a question about this procedure,
or a comment, or are you just bragging? (;>
squib
squib is offline
#3
Oct9-05, 09:53 PM
P: 40
so then 2,250,087 = 2,250,000 (1510 + V_heart)/1510
which came to .0584 m/s


My answer wasn't right =/

squib
squib is offline
#4
Oct9-05, 10:14 PM
P: 40

Dopler effect


so then 2,250,087 = 2,250,000 (1510 + V_heart)/1510
which came to .0584 m/s


My answer wasn't right =/
squib
squib is offline
#5
Oct10-05, 04:04 PM
P: 40
anyone else have any ideas?


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