Point moving along the curve y=2x^2+1

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SUMMARY

The discussion focuses on determining the rate of change of x when a point moves along the curve defined by the equation y=2x^2+1, with the y value decreasing at a rate of 2 units per second. By applying the concept of related rates and differentiating the equation, the relationship between dy/dt and dx/dt is established using the formula dy/dx = (dy/dt) / (dx/dt). The specific question posed is to find dx/dt when x equals 3/2.

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A point moves along the curve y=2x^2+1 in such a way that the y value is decreasing at the rate of 2 units per second. At what rate is x changing when x=(3/2)?
 
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mattsoto said:
A point moves along the curve y=2x^2+1 in such a way that the y value is decreasing at the rate of 2 units per second. At what rate is x changing when x=(3/2)?
What have you done so far? Do you know anything about related rates? Start by differentiating, then use the fact that:

[tex]\frac{dy}{dx}=\frac{\frac{dy}{dt}}{\frac{dx}{dt}}[/tex]

Try writing the info. given in terms of derivatives.

Alex
 
What is the given and what is the unknown? From the problem statement, you know that y and x are also functions of t.
Show what you got so far.
 

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