How to set up probability of numeric recurrence in lottery

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This discussion focuses on calculating the probability of numeric recurrence in a lottery scenario where 12 numbers are drawn from a set of values ranging from 0 to 9, with replacement. The key calculations involve determining the likelihood of specific occurrences, such as two numbers appearing three times each or one number appearing three times and another four times. The analogy of rolling dice is used to illustrate the concept, emphasizing that the probability remains constant due to the replacement of drawn numbers.

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ArfDogXYZ
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Hi,
It has been a long time, and I do not remember how to set up a probability calculation with the following variables -
take a lottery that draws 12 numbers, values 0-9 only, from a hopper that replaces the number after it is drawn, i.e. probability of each number appearing remains constant.
How do I set up an equation to determine probability of, say
2 numbers each appearing 3 times
1 number 3 times and 1 number 4 times, etc... (can be any two numbers, just want to calculate probability of it happening at all, not for specific digits.)
any help appreciated, thanks
 
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This is an easy problem. Take dice, what chance is there to get "snake eyes"? Well the 2 can occur in only one way (which is the case with the numbers you are mentioning) and so of the 36 possibilities with two dice there is only 1/36 chance that it will come on the next roll. To come up twice would be: 1/36 x 1/36 = 1/1296, but it will happen anyway!
 

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