Find acceleration when you only have a Fx

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SUMMARY

To find acceleration when only the horizontal force component (Fx) is known, and the force is applied at an angle of 25 degrees, one must first determine the total force (F) using the equation F = Fx/cos(25). The vertical component of the force (Fy) can be calculated as Fy = Fx(tan(25)). Finally, to compute acceleration, the mass of the object must be known, as acceleration (a) is derived from Newton's second law, a = F/m.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Knowledge of trigonometric functions (sine, cosine, tangent)
  • Familiarity with vector components of forces
  • Basic algebra for solving equations
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  • Study Newton's second law of motion in detail
  • Learn how to resolve forces into their components using trigonometry
  • Explore the relationship between mass and acceleration in physics
  • Practice problems involving forces at angles and their effects on motion
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Students in physics, engineers working with forces, and anyone interested in understanding the dynamics of motion involving angled forces.

monkeypretzels
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how could you possibly find accerlation when you only have a Fx and that force is being pulled at 25 degrees :eek:
 
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First of all, a "force" cannot be pulled! I presume you mean that an object is being pulled, at 25 degrees by a force with horizontal component Fx. 25 degrees to what? The x-axis? Assuming, since Fx= Fcos(25) where F is the magnitude of the force, F= Fx/cos(25) so Fy, the vertical component, is
Fy= Fsin(25)= Fx(sin(25)/cos(25))= Fx tan(25). In order to find the acceleration, you will also need to know the mass of the object.
 

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