Barrier Tunneling: Proton Transmission Coefficient

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SUMMARY

The discussion centers on calculating the transmission coefficient (T) for a 3.0 MeV proton encountering a potential energy barrier of thickness 10 femtometers (fm) and height 10 MeV. The user initially miscalculated the coefficient using the formula T=e^(-2bL) and the value of b derived from the equation b=√(8π²m(U_b-E)/h²). After realizing a mistake in their calculations, they corrected their approach, leading to the correct transmission coefficient of approximately 9.02×10^-6, as stated in the reference material.

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Kazza_765
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I can't work out what I am doing wrong in this question. Anyways, here it is:
A 3.0 MeV proton is incident on a potential energy barrier of thickness 10fm and height 10 MeV. What is the transmission coefficient T.
And here is what I have tried:
[tex]T=e^(-2bL)[/tex]
[tex]b=\sqrt{\frac{8\pi^2m(U_b-E)}{h^2}}[/tex]
[tex]b=\sqrt{\frac{8\pi^2(1.673*10^-27)\frac{10*10^6 - 3*10^6}{1.602*10^-19}}{(6.626*10^-34)^2}}[/tex]
[tex]b=3.626*10^33[/tex]
This gives me a transmission coeffecient of approximately 0, and the answer given in the book is 9.02*10^-6. Your help on this is much appreciated.
 
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Never mind, as soon as I posted it and saw my equation in front of me I worked it out. Silly mistake.
 

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