- #1
erisedk
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Homework Statement
(a) A proton at rest has energy Eproton = mprotonc2 ≈ 938 MeV. (Its momentum is zero). The protons which circulated inside the Fermilab Bevatron had energies close to 1000 GeV (1GeV = 1000 MeV). What value of γ did a Tevatron proton have?
(b) Somehow a Bevatron proton captures an electron, becoming a fast-moving hydrogen atom without changing its speed. An electron at rest has Eelectron = mec2 ≈ 0.511 MeV. What is the electron's energy in the rest frame of Fermilab's sedentary buffalo herd?
Homework Equations
##\gamma = \dfrac{1}{1-\beta^2}##
where ##β = \frac{v}{c} ##
KE = TE - BE (TE is total energy, BE is rest energy or binding energy)
The Attempt at a Solution
I just want to check if my solution is correct or not.
(a) p (momentum) = ##\sqrt{2mK}##
K = 106 MeV - 938 MeV
So, mv = ##\sqrt{2mK}##
v = ##\sqrt{\frac{2K}{m}}##
Substitute for K = 1.6 × 10-13 J and m = 1.67 × 10-27 kg and get v in m/s
Substitute v in the equation for ##\gamma##
(b) Energy = KE + BE
= ##\frac{m_e v^2}{2}## + 0.511 × 106 × 1.6 × 10-19
Substitute in v from above equation, and sub in mass of electron.
Are these calculations right?