- #1
Dantes
- 18
- 0
easy pressure and fluid problems..i swear :)
Got some (what I think) are easy pressure and fluid problems.
A 23.5 kg woman balances on one heel of a pair of high-heeled shoes.The acceleration of gravity is 9.8 m/s^2 :If the heel is circular with radius 0.225 cm,
what pressure does she exert on the floor? Answer in units of N/m^2.
On this one I been doing (23.5*9.8)/((.225 x 10^-2)^2*pi) and i get 1448.03 without the conversion to meters i get 14480348.99 which seems a little high. But 1448.03 is wrong..what am i doing wrong.
A Ping-Pong ball has a diameter of 1.79 cm and average density of 0.0377 g/cm^3.The acceleration of gravity is 9.8 m/s^2 :What force would be required to hold it completely submerged under water? Answerin units of N.
On this one I got the volume of the ping ball by 4/3*pi*(1.79/2)^3 which came out to be 3.003 cm^3 and when applying the buoyant force equation of B = p sub f * volume of the object * gravity I get 29429.4 N which comes out to be wrong. Do i need to take that number and multiply it by the area for the force? The numbers seem really high.
A homogeneous solid object floats on water with 69 percent of its volume below the surface. The same object when placed in a second liquid floats on that liquid with 66 percent of its volume below the surface. Find the density of the object. Answer in units of kg/m^3. Also what is the specific gravity of the liquid?
On this one i have no idea where to start since it doesn't give me any densities of the liquids other then water which i can only assume to be fresh water with 1.0 X 10^3.
Any help on these would be great sort of want to learn this stuff and not be doubt with the answers I get are right or not.
Got some (what I think) are easy pressure and fluid problems.
A 23.5 kg woman balances on one heel of a pair of high-heeled shoes.The acceleration of gravity is 9.8 m/s^2 :If the heel is circular with radius 0.225 cm,
what pressure does she exert on the floor? Answer in units of N/m^2.
On this one I been doing (23.5*9.8)/((.225 x 10^-2)^2*pi) and i get 1448.03 without the conversion to meters i get 14480348.99 which seems a little high. But 1448.03 is wrong..what am i doing wrong.
A Ping-Pong ball has a diameter of 1.79 cm and average density of 0.0377 g/cm^3.The acceleration of gravity is 9.8 m/s^2 :What force would be required to hold it completely submerged under water? Answerin units of N.
On this one I got the volume of the ping ball by 4/3*pi*(1.79/2)^3 which came out to be 3.003 cm^3 and when applying the buoyant force equation of B = p sub f * volume of the object * gravity I get 29429.4 N which comes out to be wrong. Do i need to take that number and multiply it by the area for the force? The numbers seem really high.
A homogeneous solid object floats on water with 69 percent of its volume below the surface. The same object when placed in a second liquid floats on that liquid with 66 percent of its volume below the surface. Find the density of the object. Answer in units of kg/m^3. Also what is the specific gravity of the liquid?
On this one i have no idea where to start since it doesn't give me any densities of the liquids other then water which i can only assume to be fresh water with 1.0 X 10^3.
Any help on these would be great sort of want to learn this stuff and not be doubt with the answers I get are right or not.