Help with Solving This Equation

  • Context: High School 
  • Thread starter Thread starter jimmie 88
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Discussion Overview

The discussion revolves around solving a specific equation related to a binomial distribution problem. Participants are seeking clarification on the correct interpretation of the equation's format and the operations involved.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant presents an equation and expresses uncertainty about whether to divide 100 by 2 or to include 2 in the multiplication.
  • Another participant attempts to clarify the equation's format, suggesting a specific grouping of terms.
  • A third participant expresses confusion regarding the grouping and indicates a willingness to help if the equation is clarified further.
  • A fourth participant points out a double posting issue and identifies the problem as related to binomial distribution.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the interpretation of the equation, and multiple viewpoints regarding its format and operations remain unresolved.

Contextual Notes

There are indications of confusion regarding the grouping of terms in the equation, which may affect the approach to solving it. The discussion also highlights the potential for miscommunication due to double posting.

jimmie 88
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Hello, could use a hand with this,
(100) (.2)X(.8) 100-X =
2

This equation is written in this format and I can't remember wether I should divide 100 by 2 or use the 2 as part of the multiplication. Thanks
 
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Is this what you are trying to write out?

[tex] (100)(0.2x)(.8)(100 - x) = 2[/tex]
 
jimmie 88 said:
Hello, could use a hand with this,
(100) (.2)X(.8) 100-X =
2
This equation is written in this format and I can't remember wether I should divide 100 by 2 or use the 2 as part of the multiplication. Thanks
I am confused by your grouping here.

if you can clear it up a bit I think I can help you out.
 
Please to do not double post! You posted this in the homework section and I responded there.

(This is a binomial distribution problem.)
 

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