Can Proportional Variation be Deduced Algebraically from Given Equations?

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SUMMARY

The discussion focuses on deducing the relationship A = jBC from the equations A = kB and A = iC, where k and i are constants dependent on B and C, respectively. By keeping C constant and varying B, and vice versa, the proportionality between A, B, and C is established. The conclusion is that A can be expressed as a product of B and C, leading to the equation A^2 = ikBC, which implies that ik = √jBC. This algebraic deduction relies on the independence of B and C as variables.

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Consider the following situation :

There are three variables A, B and C. (and i,j,k are constants )
Keeping C constant, and varying the other two, you find that

A = kB ------(1)

Now, Keeping B constant, and varying the other two, you find that

A = iC ------(2)

I know that it follows from these two observations that

A = jBC

But I am not sure how we can algebraically deduce this from the equations (1) and (2).

We get [tex]A^2 = ikBC[/tex]

Presumably, [tex]ik = \sqrt{j}BC[/tex]
But how do we deduce this?
 
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You have

[tex]A = k(C) \times B = i(B) \times C[/tex]

where k and i are functions of C and B, respectively. If B and C are independent variables then the only way k(C)B and i(B)C can be equal is if k is proportional to C and i is proportional to B. Therefore, A = jBC.
 
Thanks for the help.
 

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