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Wavelength, Frequency, and Planck's Constant

by Soaring Crane
Tags: constant, frequency, planck, wavelength
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Soaring Crane
#1
Nov3-05, 03:08 PM
P: 484
1) What is the wavelength (in meters) of an electromagnetic wave of frequency 2812571875.00MHz?
Example: 1.11e-5
LAMBDA = c/v
=(3.00*10^8 m/s)/(2812571875.00MHz*10^6 Hz/MHz) = 1.07E-7 m??

_________________________________________________________________
2) What is the wavelength (in meters) of an electromagnetic wave of frequency 7084.00MHz?
LAMBDA = c/v
=(3.00*10^8 m/s)/(7084.00MHz*10^6 Hz/MHz) = 4.23E-1 m??

_________________________________________________________________
3) How much energy is carried by a mole of photons with frequency 704.00MHz?
Give your answer in kilojoules per mole, Example: 1.11e-5
Careful with your conventions.
E = hv
=(6.626*10^-34)*(704.00MHz*10^6 Hz/MHz) = 4.665E-25 J
4.665E-25 J(1 kJ/10^-3 J)* (6.02*10^23 photons/1mol) = 2.81E-4 kJ/mol??
_________________________________________________________________

Did I express my answers with the right significant digits and calculations?
Thanks.
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Pengwuino
#2
Nov3-05, 03:53 PM
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P: 7,120
Yes, the significant digits look correct and the calculations seem correct although I don't have a calculator around at the moment.
Integral
#3
Nov3-05, 05:03 PM
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P: 7,320
You are given a lot of signifiant digits in your problem, why did you only use 3 for c? Is that c to 3 digits? There are about 8 digits of c available, why not use them?

Pengwuino
#4
Nov3-05, 05:06 PM
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P: 7,120
Wavelength, Frequency, and Planck's Constant

Quote Quote by Integral
You are given a lot of signifiant digits in your problem, why did you only use 3 for c? Is that c to 3 digits? There are about 8 digits of c available, why not use them?
I suppose its because he's using a text book and I bet he might get the answers wrong (as far as grading is concerned) if he starts using different sources for the numbers.
Ouabache
#5
Nov3-05, 06:06 PM
Sci Advisor
HW Helper
P: 1,326
Quote Quote by Soaring Crane
1) What is the wavelength (in meters) of an electromagnetic wave of frequency 2812571875.00MHz?
Example: 1.11e-5
LAMBDA = c/v
=(3.00*10^8 m/s)/(2812571875.00MHz*10^6 Hz/MHz) = 1.07E-7 m??
If your text does give constant c to more significant digits, I would use them as Integral suggests. If you are not given speed of light in your text, you can use any valid source such as NIST (national institute of standards & technology). An equally correct answer to this part is 107nm. If your question does not specify units for your answers, both solutions are good.

2) What is the wavelength (in meters) of an electromagnetic wave of frequency 7084.00MHz?
LAMBDA = c/v
=(3.00*10^8 m/s)/(7084.00MHz*10^6 Hz/MHz) = 4.23E-1 m??
I would check this again, especially your decimal place.

3) How much energy is carried by a mole of photons with frequency 704.00MHz?
Give your answer in kilojoules per mole, Example: 1.11e-5
Careful with your conventions.
E = hv
=(6.626*10^-34)*(704.00MHz*10^6 Hz/MHz) = 4.665E-25 J
4.665E-25 J(1 kJ/10^-3 J)* (6.02*10^23 photons/1mol) = 2.81E-4 kJ/mol??
Your solution is correct but your equation is not...
You should have (1 kJ/10^3J), using your equation as written, you would get 281 kJ/mol
Soaring Crane
#6
Nov4-05, 05:17 AM
P: 484
For #2, it is 4.23E-2 m?
For the constant c, my textbook gives the value in 8 decimal places, but it says that it is mostly rounded off to 3.00*10^8 and it uses this rounded off version in examples.
Ouabache
#7
Nov4-05, 05:21 PM
Sci Advisor
HW Helper
P: 1,326
Nice job on #2 !! Try solving your questions, more than one way. Then you will be able to catch things like this on your own.

If they use the rounded off version of c in their examples, for practical purposes, you probably can use it as well. If you're in doubt, ask your teacher first before handing in those questions..


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