What Force Lifts a Bicycle Wheel Over a Step?

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The discussion focuses on calculating the horizontal force required to lift a bicycle wheel over a step of height h = 0.110 m, with a weight W = 29.0 N and radius r = 0.350 m. The key to solving this problem lies in understanding the torque about the axis provided by the step, which acts as a pivot point. By analyzing the forces and torques acting on the wheel, one can determine the magnitude of the force F when the wheel begins to lose contact with the ground.

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The figure shows a bicycle wheel resting against a small step whose height is h = 0.110 m. The weight and radius of the wheel are W = 29.0 N and r = 0.350 m. A horizontal force F is applied to the axle of the wheel. As the magnitude of F increases, there comes a time when the wheel just begins to rise up and loses contact with the ground. What is the magnitude of the force when this happens?

I drew a diagram, yet I'm not even sure how to start this problem... help please! thanks!
 
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leezak said:
The figure shows a bicycle wheel resting against a small step whose height is h = 0.110 m. The weight and radius of the wheel are W = 29.0 N and r = 0.350 m. A horizontal force F is applied to the axle of the wheel. As the magnitude of F increases, there comes a time when the wheel just begins to rise up and loses contact with the ground. What is the magnitude of the force when this happens?
I drew a diagram, yet I'm not even sure how to start this problem... help please! thanks!
The step provides an axis (a line about which the wheel rotates) which divides the wheel into two parts. You have to determine how that axis divides the mass of the wheel. Then is a matter of determining the centre of mass of each part of the wheel to find the torques.

AM
 

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