Maxima and Minima for a two variable function

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SUMMARY

The discussion focuses on finding and classifying critical points of the function f(x,y) = (sin x)(cos y). The first partial derivatives are established as (cos x)(cos y) = 0 and (-sin x)(sin y) = 0. Critical points occur at x = (2k+1)π/2 for cos x = 0 and x = kπ for sin x = 0, where k is an integer. The conclusion confirms that there are infinitely many critical points due to the periodic nature of the sine and cosine functions.

PREREQUISITES
  • Understanding of partial derivatives
  • Knowledge of trigonometric functions and their properties
  • Familiarity with critical points in multivariable calculus
  • Ability to analyze periodic functions
NEXT STEPS
  • Study the classification of critical points in multivariable functions
  • Learn about the second derivative test for functions of two variables
  • Explore the implications of periodic functions in calculus
  • Investigate the graphical representation of sine and cosine functions
USEFUL FOR

Students in calculus, mathematicians analyzing multivariable functions, and educators teaching critical point analysis in trigonometric contexts.

Odyssey
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Greetings, can you guys please help me with my assignment??

I am supposed to find and classify all critical points of the function f(x,y) = (sin x)(cos y)

Now I took the first partials with repsect to x and y and they are (cos x)(cos y) = 0 and (-sin x)(sin y) = 0, respectively.

Now I know fx = 0 when either cos x = 0 or cos y = 0 and cos x = 0 when x is pi/2, -pi/2, 3pi/2, -3pi/2, ...

and fy = 0 when either sin x = 0 or sin y = 0 and sin x = 0 when x = kpi, k being integers...

But I don't know if there are infinitely many critical points or no critical points?? If there are infinitely many, where are they at??

Thanks for the help! :-p
 
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There are critical points as you showed, and there are infinitely many of them as you know from a sin(x) or cos(x) graph.
 

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