Two Masses Connected by a Pulley

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This discussion focuses on the application of Newton's Second Law (Fnet = ma) in scenarios involving two masses (m1 and m2) connected by a pulley. It clarifies that 'm' can represent either the individual mass of interest or the combined mass of the system, depending on the context of the net force being calculated. Participants emphasize the importance of identifying which object the net force applies to and the technique of cutting the rope to determine tension. Understanding these principles ensures accurate problem-solving in mechanics.

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brentd49
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I have a general question about how to apply Newton's Second Law. When we write Fnet=ma, I am sometimes unsure of myself what the 'm' is in the problem.

For instance, when two masses (m1 and m2) are connected by a pulley is 'm' equal to m1+m2, or just the mass of interest?

How can I be absolutely sure of myself when I am solving problems using Newton's Second Law?

Does this have something to do with the technique of cutting (i.e. if two people are pulling opposite ends of a rope, then by cutting the rope, one can find the rope's tension.)?
 
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brentd49 said:
How can I be absolutely sure of myself when I am solving problems using Newton's Second Law?

Newton's second law says that the net force acting on an object is equal to that object's mass times its acceleration.

Just be sure that you know which net force you are calculating, i.e. which object you are applying Newton's second law to. If Fnet refers to the net force on mass 1, then it is given by m1 * a1, by Newton's second law. If it refers to the net force on mass 2, then it is given by m2 * a2.


If you include both masses (and assume the rope has negligible mass), then you are calculating the net force on the system, and have to be sure to multiply this mass by the acceleration of the system, which is...?
 

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