Solving Linear Systems Using LDL^T Factorization: Step-by-Step Guide

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SUMMARY

The discussion focuses on solving linear systems using LDLT factorization, specifically applying it to the matrix system provided. The process involves three main steps: first, transforming the equation from LDLTX = A to DLTX = B through back substitution; second, dividing by the diagonal elements of D to obtain LTX = C; and finally, performing back substitution again to solve for X. The Cholesky decomposition is highlighted as the more complex aspect of this method.

PREREQUISITES
  • Understanding of LDLT factorization
  • Knowledge of back substitution techniques
  • Familiarity with triangular matrices
  • Basic linear algebra concepts
NEXT STEPS
  • Study the Cholesky decomposition in detail
  • Practice back substitution methods with various matrix sizes
  • Explore numerical stability in matrix factorization
  • Learn about applications of LDLT factorization in computational mathematics
USEFUL FOR

Students and professionals in mathematics, engineering, and computer science who are working with linear algebra and matrix computations, particularly those interested in numerical methods for solving linear systems.

stunner5000pt
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Use the [itex]LDL^T[/itex] factorization to solve the following linear system
[tex]\left(\begin{array}{cccc|1}4&1&-1&0&7\\1&3&-1&0&8\\-1&-1&5&2&-4\\0&0&2&4&6\end{array}\right)[/tex]
now i know ihow to get a matrix in the form LDL^T. But i was wondering how one would go about solving from there?



Please help!
 
Last edited:
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stunner5000pt said:
Use the [itex]LDL^T[/itex] factorization to solve the following linear system
[tex]\left(\begin{array}{cccc|1}4&1&-1&0&7\\1&3&-1&0&8\\-1&-1&5&2&-4\\0&0&2&4&6\end{array}\right)[/tex]
now i know ihow to get a matrix in the form LDL^T. But i was wondering how one would go about solving from there?
Please help!
That should be straight forward- the Cholesky decomposition is supposed to be the hard part! L here is a lower triangular matrix, LT is upper triangular, and D is diagonal, so going from LDLTX= A to DLTX= B is just a matter of "back substitution", starting from the value you get immediately in the last row and working up.
Since D is diagonal, going from DLTX= B to LTX= C is just dividing by the diagonal elements. Finally, since LT is upper triangular, going from LTX= C to X= D is again back substitution, this time working from the top row down.
 

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