
#1
Nov1105, 05:58 PM

P: 9

A mass of 100 g causes a vertical spring to stretch by 2.0 cm. a) find the spring constant of the spring in N/m: No picture was given to me.
Ok im not sure if this is the formula to find spring constant so is it: k= mg/x and if so the answer is k=(100)(9.81)/2.0 cm k= 490.5 N/m is this correct? 



#2
Nov1105, 06:21 PM

Mentor
P: 40,878

The formula (Hooke's law) is correct. But check your units. I recommend that you convert all quantities to standard units before plugging numbers into the formula. (What are the standard units for length and mass?)




#3
Nov1105, 06:39 PM

P: 9

Ok here is the correct solution.
k=mg/x k= (.1kg)(9.81)/.02m k= 49.1 N/m so I got the correct answer by using hooke's law? Now that I got that then for part b it asks: How much force wil cause the spring to compress by 0.5 cm? F=kx So the answer is F= (49.1N/m)(.005m)= .25 N Did I do it right? 



#4
Nov1105, 06:48 PM

Mentor
P: 40,878

find spring constant of spring in N/m.help! 



#5
Nov1105, 06:52 PM

P: 9

Thanks Doc. I might be back shortly if I have any more problems.




#6
Nov1305, 02:40 PM

P: 13

similar question:
What is the spring constant of a spring that stores 25 J of elastic potential energy when compressed by 6.0 cm from its relaxed length? I've tried using N*m = J (work) to find my Newtons and dividing by the distance: N*0.06m = 25J N = 25 / 0.06 N = 416.667 N/m = 416.667N / 0.06m N/m = 6944.444 for some reason, that's wrong. I'm wondering if perhaps the sign matters? 



#7
Nov1305, 03:09 PM

Mentor
P: 40,878





#8
Nov1305, 11:06 PM

P: 13

ah, found it! thanks for the help Doc




#9
Oct2509, 02:26 PM

P: 1

The force required to stretch a Hooke’slaw spring varies from 0 N to 52.4 N as we stretch the spring by moving one end 13.8 cm from its unstressed position. Find the force constant of the spring. Answer in units of N/m.
Cant i just Take Force final = k(change in x) 



#10
Jan2110, 01:01 PM

P: 1

Hi, so what if the spring isn't vertical? I have the mass, displacement, and frequency of the spring and I'm being asked to find the acceleration. Do I need to find the spring constant in order to do that?




#11
May711, 03:08 PM

P: 1

on what factors spring constant depends?
for example if we attatch mass to a particular spring and calculate frequency, then we cut the spring into two halves and attatch the same mass to one of the halves. is there any difference in frequency or not then? please help me out. 



#12
Oct3111, 07:32 PM

P: 1

so im doing a real life situation lab. but with poppers. (you know the little rubber ones you put inside out and let pop up and you go AH!). and all im asking is the x. when it's "Stretch like in the original problem asked in this thread would that be the hight compressed (i dont think so since it's 'compressed') the average height? Im guessing the average height




#13
Mar2712, 12:30 PM

P: 1

Hi I need help in one of these exam questions from the AQA Physics a level exam in springs constant.Unit 02  Mechanics, Materials and Waves Question Paper on question 1aiii)
http://www.aqa.org.uk/qualifications...keymaterials PLEASE HELPP!!! 



#14
Apr1112, 11:14 PM

P: 2

A teddy bear of mass 400 grams is hung from the end of a spring. The spring measures 51.0cm long in the rest position; when the teddy bear is attached to the end of the spring, the spring extends to 72.0cm. Calculate the elastic potential energy stored in the spring when extended to 72.0cm.



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