Register to reply

Dividing Vectors

by cscott
Tags: dividing, vectors
Share this thread:
cscott
#1
Nov14-05, 03:30 PM
P: 786
If I want to divide vectors and produce a scalar quotient can I go as follows:
[tex]\frac{\vec{u}}{\vec{v}} \cdot \frac{\vec{v}}{\vec{v}}[/tex]
i.e. compute the dot products and then divide
Phys.Org News Partner Science news on Phys.org
Guidelines for enhancing solar cells using surface plasmon polaritons
Trees and shrubs invading critical grasslands, diminish cattle production
Climate change will threaten fish by drying out Southwest US streams, research predicts
marlon
#2
Nov14-05, 03:58 PM
marlon's Avatar
P: 4,006
Well you do not have many options. In order to have a scalar product , you need either

a)two vectors or
b)two numbers or
c)a vector and a number

that you multiply...

The quotient of two vectors is NOT a vector nor a number. The only thing that you can do is first calculate the scalar product in the numerator and then the scalar product in the denominator. This yields two numbers (ie scalars) that you can devide...


marlon
cscott
#3
Nov14-05, 04:21 PM
P: 786
Thank you.

HallsofIvy
#4
Nov15-05, 05:37 AM
Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 39,488
Dividing Vectors

In other words, [tex]\frac{\vec{u}\cdot \vec{u}}{\vec{v}\cdot\vec{v}}[/tex].

In fact, I might be inclined to take the square root of that:
[tex]\sqrt{\frac{\vec{u}\cdot \vec{u}}{\vec{v}\cdot{\vec{v}}}[/tex].
so that you are really dividing the lengths of the two vectors.

Of course, that will not have very nice properties. Division of vectors is not normally defined. What are you doing this for?


Register to reply

Related Discussions
Dividing by 0 General Math 23
Dividing by 1 is impossible General Discussion 21
Dividing Functions General Math 3
Dividing by zero General Math 6
Dividing 0 by 0 General Discussion 6