Recent content by 0tt0UK
-
0
High School Why can't \sqrt{30-x^2} be simplified to \sqrt{30}-x?
ooh.. ok! thank you all for your help- 0tt0UK
- Post #16
- Forum: General Math
-
0
High School Why can't \sqrt{30-x^2} be simplified to \sqrt{30}-x?
thx sylas.. what would you get when multiplying (30-x2)0.5 by (2+x) or any (a+b)? An exponent, it would be ok. I cannot do it with the square root.- 0tt0UK
- Post #14
- Forum: General Math
-
0
High School Why can't \sqrt{30-x^2} be simplified to \sqrt{30}-x?
(a+b)^2 is ok but what to do when the exponent is square root ? That is what I don't get, the expansion! (2+x)\sqrt{30-x^2}- 0tt0UK
- Post #11
- Forum: General Math
-
0
High School Why can't \sqrt{30-x^2} be simplified to \sqrt{30}-x?
(a+b)^2 = (a+b)(a+b)- 0tt0UK
- Post #8
- Forum: General Math
-
0
High School Why can't \sqrt{30-x^2} be simplified to \sqrt{30}-x?
Yes I understand that, ta. But what would be the multipication between both? That is what I don't get..- 0tt0UK
- Post #5
- Forum: General Math
-
0
High School Why can't \sqrt{30-x^2} be simplified to \sqrt{30}-x?
thx sylas that is what I thought but I wasn't sure.. so if I had to multiply that by let's say (2+x). What would happen to the square root (1/2)? Add the exponents due to the multiplication (1 + 1/2 = 3/2)?- 0tt0UK
- Post #3
- Forum: General Math
-
0
High School Why can't \sqrt{30-x^2} be simplified to \sqrt{30}-x?
Hi all, I am reading about trigonometry and pythagoras.. I found this (30-x2)1/2 Would it be the same as (sqrt30 - x) ?? Is there any way to simplify it? thanks in advance- 0tt0UK
- Thread
- Simplify
- Replies: 16
- Forum: General Math
-
0
Integration and RC Step response
- ln (Vin - Vc) + const thanks very much Mark44- 0tt0UK
- Post #7
- Forum: Calculus and Beyond Homework Help
-
0
Integration and RC Step response
right!? so how would you solve \int \frac{1}{Vin - Vc}dVc ?? Would you differentiate 1/Vin-Vc in function of Vc and then integrate the result? sorry I still don't understand the "-" on the right side of the eq. thanks- 0tt0UK
- Post #5
- Forum: Calculus and Beyond Homework Help
-
0
Integration and RC Step response
du in function of Vc ? du = -1 ? is that right?- 0tt0UK
- Post #3
- Forum: Calculus and Beyond Homework Help
-
0
Integration and RC Step response
Integration Homework Statement Hi everyone, I'm new here. This is my first post. I found physicsforums when researching on google a solution for a doubt I've had when trying to solve rc step response. Basically, the RC analyse showed at...- 0tt0UK
- Thread
- Integration Rc Response Step response
- Replies: 6
- Forum: Calculus and Beyond Homework Help