Mentallic said:
the rule is \sqrt{a^2}=a for a being anything, simple or complicated. Think a bit about this rule and see if you can figure out why you can't simplify the above expression {\sqrt{30-x^2}}
Mentallic said:
Think about this, (a+b)^2=?
I was trying to give 0tt0UK an understanding of why this cannot be simplified to \sqrt{30}-x !
D H said:
The rule is \sqrt{a^2} = |a|, not \sqrt{a^2}=a, and even that rule applies for the real numbers only.
Mark44 said:
I'm with D H that \sqrt{x^2} = |x|
Consider \sqrt{(-3)^2} = \sqrt{9} = 3 = |-3|
It might be that a slight complication in pursuit of the truth can be confusing, but telling a student a rule that is incorrect is worse than confusing.
Seriously... have you guys not figured out yet what 0tt0UK's mathematical level is? He's learning about pythagoras' theorem for Christ sake! What is the point of saying "oh, but \sqrt{a^2}=|a| since... wait, you don't understand why this is true? *goes off on a massive tangent to explain something that is unnecessary for 0tt0UK's case*... but really, this won't be happening in Pythagoras' theorem because side lengths in triangles are positive... not negative, and not complex".
He has no need to learn the refined rule. It's just the same reason why a teacher would never even dare to explain to their students why such a rule doesn't work for complex numbers, since they've never heard about them before, and it would drag the lesson in the wrong direction. 0tt0UK can come back to the proper rule when necessary. Not now.
0tt0UK said:
(a+b)^2 is ok but what to do when the exponent is square root ?
0tt0UK said:
ooh.. ok! thank you all for your help
That's not what I was trying to get at
I'm trying to shed some light on why \sqrt{30-x^2}\neq \sqrt{30}-x
Think about this, in the rule \sqrt{a^2}=a (where a is a length... thus, positive)
what about if we substituted a=x+y ? Then we'll have \sqrt{(x+y)^2}=x+y
But expand the (x+y)^2 and see if you notice something. Now do the same for (\sqrt{30}-x)^2 and see what you get.