Why can't \sqrt{30-x^2} be simplified to \sqrt{30}-x?

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Discussion Overview

The discussion revolves around the simplification of the expression \(\sqrt{30-x^2}\) and whether it can be expressed as \(\sqrt{30}-x\). Participants explore the rules of square roots and exponents, particularly in the context of trigonometry and the Pythagorean theorem.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants assert that \(\sqrt{30-x^2}\) cannot be simplified to \(\sqrt{30}-x\) because the square root does not distribute over subtraction.
  • One participant questions what happens when multiplying \(\sqrt{30-x^2}\) by another expression, suggesting confusion about how to handle the square root in such cases.
  • Another participant emphasizes that the rule \(\sqrt{a^2} = |a|\) is more accurate than \(\sqrt{a^2} = a\), noting that this applies only to real numbers.
  • There is a discussion about the implications of expanding \((a+b)^2\) and how it relates to the original expression, with some participants suggesting that understanding this expansion is key to grasping why the simplification is incorrect.
  • Some participants express concern that introducing more complex rules may confuse beginners who are learning foundational concepts.

Areas of Agreement / Disagreement

Participants generally agree that \(\sqrt{30-x^2}\) cannot be simplified to \(\sqrt{30}-x\), but there is disagreement on the appropriateness of introducing more complex mathematical rules to a learner who is just starting to understand these concepts.

Contextual Notes

There are unresolved questions about the multiplication of expressions involving square roots and how to properly expand such expressions. Participants express varying levels of understanding regarding the implications of the rules discussed.

0tt0UK
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Hi all,

I am reading about trigonometry and pythagoras..

I found this (30-x2)1/2

Would it be the same as (sqrt30 - x) ??

Is there any way to simplify it?

thanks in advance
 
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You cannot simplify it any further. You cannot distribute the square root over the addition.
 
thx sylas that is what I thought but I wasn't sure..

so if I had to multiply that by let's say (2+x). What would happen to the square root (1/2)?

Add the exponents due to the multiplication (1 + 1/2 = 3/2)?
 
0tt0UK said:
so if I had to multiply that by let's say (2+x). What would happen to the square root (1/2)?

So you will have [tex](2+x)\sqrt{30-x^2}[/tex] ??
Nothing happens to the square root :-p

Oh and by the way, the rule is [tex]\sqrt{a^2}=a[/tex] for a being anything, simple or complicated. Think a bit about this rule and see if you can figure out why you can't simplify the above expression.
 
Mentallic said:
...Think a bit about this rule and see if you can figure out why you can't simplify the above expression.

Yes I understand that, ta.

But what would be the multipication between both? That is what I don't get..
 
Think about this, [tex](a+b)^2=?[/tex]
 
Mentallic said:
Oh and by the way, the rule is [tex]\sqrt{a^2}=a[/tex] for a being anything, simple or complicated.
The rule is [tex]\sqrt{a^2} = |a|[/tex], not [tex]\sqrt{a^2}=a[/tex], and even that rule applies for the real numbers only.
 
Mentallic said:
Think about this, [tex](a+b)^2=?[/tex]

(a+b)^2 = (a+b)(a+b)
 
lol ok I wasn't expecting that answer. Expand it!
 
  • #10
D H said:
The rule is [tex]\sqrt{a^2} = |a|[/tex], not [tex]\sqrt{a^2}=a[/tex], and even that rule applies for the real numbers only.

DH let's not get picky now, are you trying to confuse him?

0tt0UK said:
I am reading about trigonometry and pythagoras..

Oh and p.s. what I meant by complicated was that [itex]a[/itex] could be a function of anything more complicated, such as [itex]\sqrt{30}-x[/itex] for example :wink:
(not complex numbers)...
 
  • #11
[tex](a+b)^2[/tex] is ok but what to do when the exponent is square root ?


That is what I don't get, the expansion!

[tex] (2+x)\sqrt{30-x^2}[/tex]
 
  • #12
I'm with D H that [tex]\sqrt{x^2} = |x|[/tex]
Consider [tex]\sqrt{(-3)^2} = \sqrt{9} = 3 = |-3|[/tex]
It might be that a slight complication in pursuit of the truth can be confusing, but telling a student a rule that is incorrect is worse than confusing.
 
  • #13
0tt0UK said:
[tex](a+b)^2[/tex] is ok but what to do when the exponent is square root ?

There's nothing you can do. (a+b)0.5 cannot be simplified further.

That is what I don't get, the expansion!

[tex] (2+x)\sqrt{30-x^2}[/tex]

That isn't an expansion. It's just writing (30-x2)0.5 using a square root sign instead of the exponent.

Cheers -- sylas
 
  • #14
sylas said:
There's nothing you can do. (a+b)0.5 cannot be simplified further.



That isn't an expansion. It's just writing (30-x2)0.5 using a square root sign instead of the exponent.

Cheers -- sylas

thx sylas.. what would you get when multiplying (30-x2)0.5 by (2+x) or any (a+b)?

An exponent, it would be ok. I cannot do it with the square root.
 
  • #15
0tt0UK said:
thx sylas.. what would you get when multiplying (30-x2)0.5 by (2+x) or any (a+b)?

An exponent, it would be ok. I cannot do it with the square root.

You can't simply the multiplication either. The expressions you describe are:
[tex]\begin{align*}<br /> (2+x)(30-x^2)^{0.5} \\<br /> (a+b)(30-x^2)^{0.5}<br /> \end{align*}[/tex]​
Neither of those expressions can be simplified.
 
  • #16
sylas said:
...
Neither of those expressions can be simplified.

ooh.. ok! thank you all for your help
 
  • #17
Mentallic said:
the rule is [tex]\sqrt{a^2}=a[/tex] for a being anything, simple or complicated. Think a bit about this rule and see if you can figure out why you can't simplify the above expression {[tex]\sqrt{30-x^2}[/tex]}
Mentallic said:
Think about this, [tex](a+b)^2=?[/tex]
I was trying to give 0tt0UK an understanding of why this cannot be simplified to [tex]\sqrt{30}-x[/tex] !

D H said:
The rule is [tex]\sqrt{a^2} = |a|[/tex], not [tex]\sqrt{a^2}=a[/tex], and even that rule applies for the real numbers only.
Mark44 said:
I'm with D H that [tex]\sqrt{x^2} = |x|[/tex]
Consider [tex]\sqrt{(-3)^2} = \sqrt{9} = 3 = |-3|[/tex]
It might be that a slight complication in pursuit of the truth can be confusing, but telling a student a rule that is incorrect is worse than confusing.
Seriously... have you guys not figured out yet what 0tt0UK's mathematical level is? He's learning about pythagoras' theorem for Christ sake! What is the point of saying "oh, but [tex]\sqrt{a^2}=|a|[/tex] since... wait, you don't understand why this is true? *goes off on a massive tangent to explain something that is unnecessary for 0tt0UK's case*... but really, this won't be happening in Pythagoras' theorem because side lengths in triangles are positive... not negative, and not complex".
He has no need to learn the refined rule. It's just the same reason why a teacher would never even dare to explain to their students why such a rule doesn't work for complex numbers, since they've never heard about them before, and it would drag the lesson in the wrong direction. 0tt0UK can come back to the proper rule when necessary. Not now.

0tt0UK said:
[tex](a+b)^2[/tex] is ok but what to do when the exponent is square root ?
0tt0UK said:
ooh.. ok! thank you all for your help

That's not what I was trying to get at :-p
I'm trying to shed some light on why [tex]\sqrt{30-x^2}\neq \sqrt{30}-x[/tex]

Think about this, in the rule [tex]\sqrt{a^2}=a[/tex] (where a is a length... thus, positive)
what about if we substituted a=x+y ? Then we'll have [tex]\sqrt{(x+y)^2}=x+y[/tex]

But expand the [tex](x+y)^2[/tex] and see if you notice something. Now do the same for [tex](\sqrt{30}-x)^2[/tex] and see what you get.
 

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