Recent content by 1bigman

Ah yes of course! Many thanks for the help guys!

Homework Statement We have a light rigid pendulum with length ##l##. A mass ##M## is placed at the end and a mass ##m## is placed a distance ##x## from the pivot. What is the period of the pendulum? Homework EquationsThe Attempt at a Solution Reduce the problem to a single mass situation...

My apologies. Fairly new round here... I've figured it out now, but many thanks anyways

Homework Statement We have a particle mass ##m## with kinetic energy ##k## colliding with a stationary particle of mass ##2m##. The collision creates a composite mass of ##\sqrt{17}m##. Find the value of ##k## Homework EquationsThe Attempt at a Solution I have tried using mass-energy...

Ah, turns out the moment of inertia was incorrect...

Homework Statement We have a cubical hollow box, edge length ##a## suspended horizontally from a frictionless hinge along one of its edges. The box is displaced slightly and undergoes SHM. Show that the period of the oscillation is given by ## T = 2\pi \sqrt{\frac{7\sqrt{2}a}{9g}} ## Homework...

My apologies. The question for the first part is as follows: A spherical interface of radius R separates two media of refractive indices ##n_1## and ##n_2##. Show that, in the paraxial approximation, a point object on the optical axis a distance ##u## from the interface in the first medium...

Ah, yes. So I'm guessing the equation calculated in the first part of the question is irrelevant in this circumstance? Otherwise I can't seem to find how the image gives any relation to ##r##.

True, but we can always give our answer in terms of ##f## as that is mentioned in the question?

My sketch had the lens in the mercury with rays of light being refracted as normal and then reflected and following it's path back to the source. Could it be as simple as using the derived expression in the question and the lens makers to solve for r and n?

The relation was obtained by considering a spherical interface separating two different media. The image is formed at a distance ##v## in the sphere. My reasoning for not using the standard lens maker of ##\frac{1}{f} = \left(\frac{n_1}{n_2} -1\right)\left(\frac{1}{r_1}-\frac{1}{r_2}\right) ##...

Homework Statement A biconvex lens of refractive index ##n## and radius of curvature ##r## and focal length ##f## floats horizontally on liquid mercury such that its lower surface is effectively a spherical mirror. A point object on the optical axis a distance ##u## away is then found to...