Recent content by 31415
-
3
Roots of -8: Solving with Exponential Form
yeah I know that - ... e^i*pi = -1 8 e^i*pi = -8 e^2*pi*k =1 for k: 0,1,2,3...- 31415
- Post #7
- Forum: Calculus and Beyond Homework Help
-
3
Roots of -8: Solving with Exponential Form
ah i see when I take the principle arguments of each root then the answers agree - thanks all. Still don't understand why he decided to do it like that but I guess it doesn't matter :)- 31415
- Post #5
- Forum: Calculus and Beyond Homework Help
-
3
Roots of -8: Solving with Exponential Form
Homework Statement I'm supposed to find the 6 roots of -8 + 0i we are told the usual method of for these problems is to put the complex number into it's exponential form like so z = |z|exp( i(θ+2πk)) where k: [0 to n-1] then put it to the relevant power 'n' z1/n = |z|1/nexp(( i(θ+2πk)/n)...- 31415
- Thread
- Roots
- Replies: 8
- Forum: Calculus and Beyond Homework Help