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Cool, thanks a lot man :)

So ill just find power by multiplying 1200 by 10m to get 12000J, but what about the power dissipated? i found power to be 66.67 by dividing work by time, but I am not sure if that's the dissipation or not

Mmmm...Good ol' work and power A 1200N force is applied parallel to a horizontal surface. It pushes an 80N box 10m across the surface. What work is done? What power is dissipated in 3 minutes? What i did for this one is subtract the 80N force from the 1200N force and multiply it by 10m...

Wow! Excuse my terrible english in the previous statement..."my teachers hasnt...", you must think I am retarded

this is a tough one, anybody?

Wow, my teachers hasnt given us those equations so I am really not sure how to use them

Problem: A 65kg create is to be accelerated at 7 m/s/s up an incline making an angle of 25 degrees with the horizontal. If the coefficient of sliding friction is .2, what force is needed to accomplish this motion? Well I've tried manipulating this equation to give me either a Ff or an Fn for...

Before you get all worked up, I am just going to let you know that this isn't homework. Here is my problem : A projectile is fired at a 20 degree angle with a velocity of 15 m/s. What is the total time of flight? What is the distance of its hight? How far did it travel in the horizontal...