Coefficient of sliding friction without an Fa

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SUMMARY

The problem involves calculating the force required to accelerate a 65 kg crate up a 25-degree incline with a coefficient of sliding friction of 0.2 and an acceleration of 7 m/s². To solve this, one must consider the forces acting on the crate, including gravitational force, normal force, and frictional force. The equation Ff = μFn is essential, where Ff is the frictional force and Fn is the normal force, which can be derived from the weight of the crate and the incline angle. A free body diagram (FBD) is crucial for visualizing the forces involved in this scenario.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Knowledge of forces on inclined planes
  • Familiarity with free body diagrams (FBD)
  • Basic grasp of friction coefficients and their application
NEXT STEPS
  • Calculate the normal force (Fn) acting on the crate on the incline
  • Determine the gravitational force components (Fgcos25 and Fgsin25)
  • Apply the frictional force formula Ff = μFn to find the required frictional force
  • Combine all forces to calculate the total force (Fa) needed for the acceleration
USEFUL FOR

Students in physics, engineers working on mechanical systems, and anyone studying dynamics involving inclined planes and friction.

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Problem: A 65kg create is to be accelerated at 7 m/s/s up an incline making an angle of 25 degrees with the horizontal. If the coefficient of sliding friction is .2, what force is needed to accomplish this motion?

Well I've tried manipulating this equation to give me either a Ff or an Fn for the mu=Ff/Fn equation. Problem is where its on an incline, i need Facos25 and Fasin25, but i don't have an Fa, all I am given is a 7m/s/s. I am a bit stuck and need some help here
Thanks in advance
 
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this is a tough one, anybody?
 
draw a FBD and then break it down into all the forces acting on it
 

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